document.write( "Question 988413: How much 20% acid solution and how much 35% acid solution should be used to fill an order for 25 liters of a 26% acid solutions \n" ); document.write( "
Algebra.Com's Answer #608975 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x=20% acid \n" ); document.write( "25-x=35% acid \n" ); document.write( ".20x+(0.35)(25-x)=0.25*26 \n" ); document.write( ".20x+8.75-.35x=6.50 \n" ); document.write( "-0.15x=-2.25 \n" ); document.write( "x=15 liters of 20% acid \n" ); document.write( "25-x=10 liters of 35% acid. \n" ); document.write( "=== \n" ); document.write( "Pure acid \n" ); document.write( "15*0.20+10(.35)=3+3.5=6.5 \n" ); document.write( "25*.26=6.5 check \n" ); document.write( " |