document.write( "Question 988413: How much 20% acid solution and how much 35% acid solution should be used to fill an order for 25 liters of a 26% acid solutions \n" ); document.write( "
Algebra.Com's Answer #608975 by Boreal(15235)\"\" \"About 
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x=20% acid
\n" ); document.write( "25-x=35% acid
\n" ); document.write( ".20x+(0.35)(25-x)=0.25*26
\n" ); document.write( ".20x+8.75-.35x=6.50
\n" ); document.write( "-0.15x=-2.25
\n" ); document.write( "x=15 liters of 20% acid
\n" ); document.write( "25-x=10 liters of 35% acid.
\n" ); document.write( "===
\n" ); document.write( "Pure acid
\n" ); document.write( "15*0.20+10(.35)=3+3.5=6.5
\n" ); document.write( "25*.26=6.5 check
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