document.write( "Question 988102: solve for x. 2^(2sinx)+2^(sinx)-6=0 \n" ); document.write( "
Algebra.Com's Answer #608916 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
Use a substitution,
\n" ); document.write( "\"u=2%5E%28sin%28x%29%29\"
\n" ); document.write( "\"u%5E2=2%5E%282sin%28x%29%29\"
\n" ); document.write( "So then,
\n" ); document.write( "\"u%5E2%2Bu-6=0\"
\n" ); document.write( "\"%28u%2B3%29%28u-2%29=0\"
\n" ); document.write( "Two \"u\" solutions:
\n" ); document.write( "\"u%2B3=0\"
\n" ); document.write( "\"u=-3\"
\n" ); document.write( "\"2%5E%28sin%28x%29%29=-3\"
\n" ); document.write( "Not a possible solution in x.
\n" ); document.write( ",
\n" ); document.write( ",
\n" ); document.write( "\"u-2=0\"
\n" ); document.write( "\"u=2\"
\n" ); document.write( "\"2%5E%28sin%28x%29%29=2\"
\n" ); document.write( "\"sin%28x%29=1\"
\n" ); document.write( "\"highlight%28x=pi%2F2+%2B+%282pi%29%2Ak%29\" where \"k\" is an integer.\r
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