document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=11979>Question 11979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i need help with evaluating functions. Can you help me with this problem\r<BR>\n" );
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document.write( "f(x)=1/2x+2   the x value is -6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6089 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Please read my Lesson on this site on functions, it will help you.\r<BR>\n" );
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document.write( "Anyway, f(x) = (1/2)x + 2\r<BR>\n" );
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document.write( "this says...whatever the value is, here it is written as \"x\", in the f(x) bit, then what you do is multiply it by (1/2) and then add 2...the equation!\r<BR>\n" );
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document.write( "so f(-6) = (1/2)(-6) + 2 which becomes<BR>\n" );
document.write( "f(-6) = -3 + 2<BR>\n" );
document.write( "f(-6) = -1\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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