document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=988311>Question 988311</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 136 inches. If the length is four less than five times the width, what is the area of the rectangle? Thanks for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #608864 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=608864\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "W=width; L=length=5W-4; P=perimeter=136 inches<BR>\n" );
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document.write( "P=2(L+W)Substitute for L<BR>\n" );
document.write( "136 in=2((5W-4)+W) Divide each side by 2.<BR>\n" );
document.write( "68 in=6W-4 Add 4 in to each side.<BR>\n" );
document.write( "72 in=6W<BR>\n" );
document.write( "12 in=W<BR>\n" );
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document.write( "L=5W-4in=5(12)-4=60-4=56 in<BR>\n" );
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document.write( "Area=LW=(56in)(12in)=672in^2<BR>\n" );
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document.write( "ANSWER: The area is 672 square inches.<BR>\n" );
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