document.write( "Question 988181: How many milliliters of water must be mixed with 26 milliliters of a 34% sulfuric acid solution to obtain a 22% sulfuric acid solution? \n" ); document.write( "
Algebra.Com's Answer #608783 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "How many milliliters of water must be mixed with 26 milliliters of a 34% sulfuric acid solution to obtain a 22% sulfuric acid solution?
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Let amount of water be W\r\n" );
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Solve using any of the two equations:
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\n" ); document.write( "Equation 1
0W + .34(26) = .22(W + 26)\r\n" );
document.write( "        8.84 = .22W + 5.72\r\n" );
document.write( "        .22W = 8.84 - 5.72\r\n" );
document.write( "        .22W = 3.12\r\n" );
document.write( "Solve for W, the amount of water\r\n" );
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\n" ); document.write( "OR\r
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\n" ); document.write( "\n" ); document.write( "Equation 2
W + .66(26) = .78(W + 26)\r\n" );
document.write( "  W + 17.16 = .78W + 20.28\r\n" );
document.write( "   W - .78W = 20.28 - 17.16\r\n" );
document.write( "       .22W = 3.12\r\n" );
document.write( "Solve for W, the amount of water
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