document.write( "Question 988181: How many milliliters of water must be mixed with 26 milliliters of a 34% sulfuric acid solution to obtain a 22% sulfuric acid solution? \n" ); document.write( "
Algebra.Com's Answer #608783 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "How many milliliters of water must be mixed with 26 milliliters of a 34% sulfuric acid solution to obtain a 22% sulfuric acid solution? \n" ); document.write( " Let amount of water be W\r\n" ); document.write( "Solve using any of the two equations: \n" ); document.write( " \n" ); document.write( "Equation 1 0W + .34(26) = .22(W + 26)\r\n" ); document.write( " 8.84 = .22W + 5.72\r\n" ); document.write( " .22W = 8.84 - 5.72\r\n" ); document.write( " .22W = 3.12\r\n" ); document.write( "Solve for W, the amount of water\r\n" ); document.write( " \n" ); document.write( "OR\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Equation 2 W + .66(26) = .78(W + 26)\r\n" ); document.write( " W + 17.16 = .78W + 20.28\r\n" ); document.write( " W - .78W = 20.28 - 17.16\r\n" ); document.write( " .22W = 3.12\r\n" ); document.write( "Solve for W, the amount of water\n" ); document.write( " |