document.write( "Question 988199: Two cyclists, 168 mi apart, start riding towards each other at the same time. One cycles twice as fast as the other. If they meet 4 hr later, at what average speed is each cyclist traveling? \n" ); document.write( "
Algebra.Com's Answer #608779 by ikleyn(52803)\"\" \"About 
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\n" ); document.write( "Let  x  be the average speed of the slower cyclist,  in  mph (miles per hour). \r
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\n" ); document.write( "\n" ); document.write( "Then the average speed of the other cyclist is  2x  mph,  according to the condition.\r
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\n" ); document.write( "\n" ); document.write( "Since the two cyclists are riding towards each other,  their relative rate is \r
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\n" ); document.write( "\n" ); document.write( "x + 2x = 3x mph.\r
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\n" ); document.write( "\n" ); document.write( "So,  the distance between the cyclists decreases in  3x  miles each hour.  Since they met  4  hours later,  the distance they both covered was  4*3x = 12x  miles. \r
\n" ); document.write( "\n" ); document.write( "It is exactly the distance between their starting points,  i.e.  168 mi.  So,  you have an equation \r
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\n" ); document.write( "\n" ); document.write( "12x = 168, \r
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\n" ); document.write( "\n" ); document.write( "which gives  x = \"168%2F12\" = 14 mph.\r
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\n" ); document.write( "\n" ); document.write( "Hence,  the average speed of the slower cyclist is  14 mph,  and that of the other cyclist is  2*14 = 28 mph. \r
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\n" ); document.write( "\n" ); document.write( "The problem is solved.\r
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