document.write( "Question 84530This question is from textbook College Agebra
\n" ); document.write( ": Find the real values of x such that f(x)=0 (directions).\r
\n" ); document.write( "\n" ); document.write( "f(x)=3/x-1 + 4/x-2 - - I don't even know where to begin on this problem. the answer they gave is 10/7 and I'm really confused on that....
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Algebra.Com's Answer #60873 by bucky(2189)\"\" \"About 
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Just set f(x) equal to zero. When you do that the given equation becomes:
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\n" ); document.write( "\"3%2F%28x-1%29+%2B+4%2F%28x-2%29+=+0\"
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\n" ); document.write( "Now get rid of the denominators by multiplying all terms (on both sides) of this equation
\n" ); document.write( "by \"%28x-1%29%2A%28x-2%29\". When you do that multiplication you get:
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\n" ); document.write( "Note that the right side of the equation remains zero because 0 times anything is still
\n" ); document.write( "zero. Note also that you can now cancel the terms in the denominator with the same term
\n" ); document.write( "in the numerator. The result is:
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\n" ); document.write( "And the equation reduces to:
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\n" ); document.write( "\"3%2A%28x-2%29+%2B+4%2A%28x-1%29+=+0\"
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\n" ); document.write( "Multiply out the terms to get:
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\n" ); document.write( "3x - 6 + 4x - 4 = 0
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\n" ); document.write( "Combine the x terms and the equation becomes:
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\n" ); document.write( "7x – 6 – 4 = 0
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\n" ); document.write( "Combine the -6 with the -4 and the equation further becomes:
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\n" ); document.write( "7x – 10 = 0
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\n" ); document.write( "Eliminate the -10 from the left side by adding +10 to both sides. This makes the equation:
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\n" ); document.write( "7x = 10
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\n" ); document.write( "Finally, solve for x by dividing both sides of the equation by 7 which is the multiplier
\n" ); document.write( "of the x term. The division results in the answer:
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\n" ); document.write( "\"x=10%2F7\"
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\n" ); document.write( "Hope this helps you understand the problem.
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