document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=988054>Question 988054</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One side of a triangle is twice as long as the second side. The remaining side is 4 centimeters greater than the second side. The perimeter of the triangle is 24 centimeters. Find the length of each side of the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #608694 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=608694\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One side of a triangle is twice as long as the second side. The remaining side is 4 centimeters greater than the second side. The perimeter of the triangle is 24 centimeters. Find the length of each side of the triangle <BR>\n" );
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document.write( "2nd side: x<BR>\n" );
document.write( "1st side: 2x<BR>\n" );
document.write( "3rd side:: 2x+4<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x + 2x + 2x+4 = 24<BR>\n" );
document.write( "5x = 20<BR>\n" );
document.write( "x = 4 cm (2nd side)<BR>\n" );
document.write( "2x = 8 cm (1st side)<BR>\n" );
document.write( "2x+4 = 12 cm (3rd side)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );