document.write( "Question 987959: Clark is twice as old as Matt. In two years the sum of their ages
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document.write( "will be five times as much as what Matt's age was four years ago.
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document.write( "How old is each now? \n" );
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Algebra.Com's Answer #608641 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "Since Mark and Matt have names that start with the same first \r\n" ); document.write( "letter I have changed Mark's name to Clark.\r\n" ); document.write( " \n" ); document.write( "Clark is twice as old as Matt. In two years the sum of their \n" ); document.write( "ages will be five times as much as what Matt's age was four \n" ); document.write( "years ago. How old is each now? \n" ); document.write( " \n" ); document.write( "Clark is twice as old as Matt. \n" ); document.write( " \r\n" ); document.write( "C = 2M\r\n" ); document.write( " \n" ); document.write( "In two years the sum of their ages... \n" ); document.write( " \r\n" ); document.write( "In two years Clark will be C+2 and Matt will be M+2 and \r\n" ); document.write( "the sum of their ages will (C+2)+(M+2) which equals \r\n" ); document.write( "\r\n" ); document.write( "C+M+4 <-- sum of their ages in two years.\r\n" ); document.write( " \n" ); document.write( "...will be five times as much as what Matt's age was four \n" ); document.write( "years ago. \n" ); document.write( " \r\n" ); document.write( "M-4 <-- what Matt's age was four years ago.\r\n" ); document.write( "\r\n" ); document.write( "So we are told that C+M+4 is 5 times as much as M-4. So\r\n" ); document.write( "\r\n" ); document.write( "C+M+4 = 5(M-4)\r\n" ); document.write( "\r\n" ); document.write( "Now we have this system of equations to solve:\r\n" ); document.write( "\r\n" ); document.write( "\n" ); document.write( " |