document.write( "Question 987898: Aldo has scored
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document.write( "83
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document.write( ",
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document.write( "69
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document.write( ",
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document.write( "92
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document.write( ",
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document.write( "92
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document.write( ", and
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document.write( "90
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document.write( " on his previous five tests. What score does he need on his next test so that his average (mean) is
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document.write( "81
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document.write( "? \n" );
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Algebra.Com's Answer #608578 by solver91311(24713) You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Presuming that the 6th test is of equal weight to the first 5, that is, the 6th test isn't a final exam that counts as two tests or some other such scheme, then the total score for all 6 tests must be 6 times 81 in order to have an average of 81.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( "My calculator said it, I believe it, that settles it\r \n" ); document.write( "\n" ); document.write( " |