document.write( "Question 987826: Selma paid a bill of $2.70 in quarters, dimes, and pennies. She had five less quarters than dimes, and four less quarters than pennies. How many coins of each kind did she use to pay the bill? \n" ); document.write( "
Algebra.Com's Answer #608545 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! dimes=x \n" ); document.write( "quarters=x-5 \n" ); document.write( "pennies=x-1 \n" ); document.write( ".10x+.25(x-5)+.01x-.01=2.70 \n" ); document.write( ".10x+.25x-1.25+.01x-.01=2.70 \n" ); document.write( "0.36x-1.26=2.70 \n" ); document.write( "0.36 x=3.96 \n" ); document.write( "x=11 dimes \n" ); document.write( "x-5= 6 quarters \n" ); document.write( "x-1=10 pennies \n" ); document.write( "That is $1.10+$1.50+$0.10=$2.70 \n" ); document.write( " \n" ); document.write( " |