document.write( "Question 987684: A car traveled from city X to city Y at a uniform speed of 120 miles/ hr. The car then travels from city Y to city Z at a uniform speed of eof 100miles/ hr. If the distance the car travelled city X and Y is twice the distance the car travelled between city Y and Z , what is the average speed in miles per hour the car travelled between city X and Z\r
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document.write( "Many thanks for your help
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document.write( "Manoj \n" );
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Algebra.Com's Answer #608524 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A car traveled from city X to city Y at a uniform speed of 120 miles/ hr. \n" ); document.write( " The car then travels from city Y to city Z at a uniform speed of of 100miles/ hr. \n" ); document.write( " If the distance the car travelled city X and Y is twice the distance the car travelled between city Y and Z , what is the average speed in miles per hour the car travelled between city X and Z \n" ); document.write( ": \n" ); document.write( "let a = the average speed of the whole trip \n" ); document.write( "let d = the distance from y to z \n" ); document.write( " we know the dist from x to y, is twice the dist from y to z, therefore \n" ); document.write( "2d = the distance from x to y \n" ); document.write( "and \n" ); document.write( "3d = the total distance from x to z \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( "xy time + yz time = total time \n" ); document.write( " \n" ); document.write( "multiply by 600a \n" ); document.write( "600a* \n" ); document.write( "Cancel the denominators \n" ); document.write( "5a(2d) + 6ad = 600(3d) \n" ); document.write( "10ad + 6ad = 1800d \n" ); document.write( "16ad = 1800d \n" ); document.write( "simplify divide both sides by d \n" ); document.write( "16a = 1800 \n" ); document.write( "a = 1800/16 \n" ); document.write( "a = 112.5 mph av speed for x to z \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "We can confirm this by choosing a value for d, say 100 mi, and finding the times \n" ); document.write( " \n" ); document.write( "1.67 + 1 = 2.67 \n" ); document.write( ": \n" ); document.write( "Equation will be correct for any value of d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |