document.write( "Question 987697: Log(x+1)-log(x-1)=log 3 \n" ); document.write( "

Algebra.Com's Answer #608450 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Use the rule:
\n" ); document.write( " $\"+log%28a%29+-+log%28b%29+=+log%28+a%2Fb+%29+\"$
\n" ); document.write( "-----------------------------
\n" ); document.write( " $\"+log%28+x%2B1+%29+-+log%28+x-1+%29+=+log%28+3+%29+\"$
\n" ); document.write( " $\"+log+%28+%28+x%2B1+%29+%2F+%28+x-1+%29+%29+=+log+%283%29+\"$
\n" ); document.write( " $\"+%28+x%2B1+%29+%2F+%28+x-1+%29+=+3+\"$
\n" ); document.write( " $\"+x+%2B+1+=+3%2A%28+x-1+%29+\"$
\n" ); document.write( " $\"+x+%2B+1+=+3x+-+3+\"$
\n" ); document.write( " $\"+2x+=+4+\"$
\n" ); document.write( " $\"+x+=+2+\"$
\n" ); document.write( "-------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+log%28+x%2B1+%29+-+log%28+x-1+%29+=+log%28+3+%29+\"$
\n" ); document.write( " $\"+log%28+2%2B1+%29+-+log%28+2-1+%29+=+log%28+3+%29+\"$
\n" ); document.write( " $\"+log%28+3+%29+-+log%28+1+%29+=+log%28+3+%29+\"$
\n" ); document.write( " $\"+log%28+3+%29+-+0+=+log%28+3+%29+\"$
\n" ); document.write( " $\"+3+=+3+\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );