document.write( "Question 987694: the width of a rectangle is 2m less than the length.the area is 80cm square,find the lengths of the base and width \n" ); document.write( "

Algebra.Com's Answer #608447 by Felixozabs(1) $\"\"$ $\"About$

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Let length =y
\n" ); document.write( "let width =x
\n" ); document.write( " recall Y x X=80
\n" ); document.write( " x=y-2 i.e 2cm less than y
\n" ); document.write( " y x (y-2)=80
\n" ); document.write( "y^2 -2y=80
\n" ); document.write( "y^2 -2y-80=0
\n" ); document.write( "(y-10)(y+8)=0
\n" ); document.write( "therefore y=10
\n" ); document.write( "recall that x=(y-2)=80
\n" ); document.write( "if y=10 then x=10-2=8
\n" ); document.write( "length=10
\n" ); document.write( "width=8 \n" ); document.write( "

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