document.write( "Question 987678: Let x represent the side length of a square. Find a regular polygon with side length x whose perimeter is twice the perimeter of the square. Find a regular polygon with side length x whose perimeter is three times the length of the square.
\n" ); document.write( "I just can't figure out how to calculate that when I don't know what type of polygon and how many sides it has?? Thanks for any help \n" ); document.write( "
Algebra.Com's Answer #608425 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "If the side lengths are the same, the only way for a polygon to have a perimeter twice as large as the square is for the polygon to have twice as many sides as the square. There are 4 sides on a square, so the polygon with twice the perimeter must have how many sides?\r
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\n" ); document.write( "\n" ); document.write( "John
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\n" ); document.write( "My calculator said it, I believe it, that settles it\r
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