document.write( "Question 987648: A pipe 11 m long and of radius r = 5 cm is to be coated by insulation material to a thickness of δr = 1 mm. Approximate the volume δV of insulation material required in m^3. \r
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Algebra.Com's Answer #608375 by ikleyn(52788)\"\" \"About 
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\n" ); document.write( "First,  estimate the surface area of the tube.  Is is\r
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\n" ); document.write( "\n" ); document.write( "\"pi%2Ar%5E2%2AL\" = \"3.14%2A0.05%5E2%2A11\" = 0.08635 \"m%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "To get the volume of the required insulation material,  multiply this surface area by the thickness of  1 mm = 0.001 m.  It gives you the answer:\r
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\n" ); document.write( "\n" ); document.write( "0.08635*0.001 = 0.0008635 \"m%5E3\". \r
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\n" ); document.write( "\n" ); document.write( "In cubic centimeters,  it is  \"0.0008635%2A10%5E6\" = 863.5 \"cm%5E3\".\r
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