document.write( "Question 987646: Given functions f and g satisfying
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Algebra.Com's Answer #608372 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
(f * g)(x) = f(x)*g(x)\r
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\n" ); document.write( "\n" ); document.write( "(f * g)'(x) = [f(x)*g(x)]' ... apply the derivative\r
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\n" ); document.write( "\n" ); document.write( "(f * g)'(x) = f ' (x)*g(x) + f(x)*g ' (x) ... use the product rule\r
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\n" ); document.write( "\n" ); document.write( "(f * g)'(3) = f ' (3)*g(3) + f(3)*g ' (3) ... plug in x = 3\r
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\n" ); document.write( "\n" ); document.write( "(f * g)'(3) = 4*2 + 3*2 ... make the proper substitutions (based on the values given)\r
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\n" ); document.write( "\n" ); document.write( "(f * g)'(3) = 8+6\r
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\n" ); document.write( "\n" ); document.write( "(f * g)'(3) = 14\r
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\n" ); document.write( "\n" ); document.write( "(f/g)(x) = f(x)/g(x)\r
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\n" ); document.write( "\n" ); document.write( "(f/g)'(x) = [f(x)/g(x)]' ... apply the derivative\r
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\n" ); document.write( "\n" ); document.write( "(f/g)'(x) = [f ' (x)*g(x) - f(x)*g ' (x)]/[g(x)]^2 ... use the quotient rule\r
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\n" ); document.write( "\n" ); document.write( "(f/g)'(3) = [f ' (3)*g(3) - f(3)*g ' (3)]/[g(3)] ... plug in x = 3\r
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\n" ); document.write( "\n" ); document.write( "(f/g)'(3) = [4*2 - 3*2]/[2^2] ... make the proper substitutions (based on the values given)\r
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\n" ); document.write( "\n" ); document.write( "(f/g)'(3) = (8-6)/4\r
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\n" ); document.write( "\n" ); document.write( "(f/g)'(3) = 2/4\r
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\n" ); document.write( "\n" ); document.write( "(f/g)'(3) = 1/2
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