document.write( "Question 987601: Mr. X had a habit of spending money according to dates. i. e. If date is 19 he was spending Rs.19 and if date is 15, he was spending Rs. 15. \r
\n" ); document.write( "\n" ); document.write( "One night he calculated total spending of 5 consecutive days - Monday to Friday and he found that he spent Rs. 61 in 5 days.\r
\n" ); document.write( "\n" ); document.write( "So, identify the dates.???
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Algebra.Com's Answer #608314 by ikleyn(52810)\"\" \"About 
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\n" ); document.write( "Answer.  There is only one solution:\r
\n" ); document.write( "\n" ); document.write( "              27 and 28  of February and  1, 2,  and  3  of March.\r
\n" ); document.write( "\n" ); document.write( "              (27 + 28 + 1 + 2 + 3 = 61). \r
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\n" ); document.write( "\n" ); document.write( "If these days would be inside one month,  then the dates are  (x-2),  (x-1),  x,  (x+1)  and  (x+2),  where x is the date of the middle of  5 days. \r
\n" ); document.write( "\n" ); document.write( "Then the sum must be multiple of  5,  since \r
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\n" ); document.write( "\n" ); document.write( "(x-2) + (x-1) + x + (x+1) + (x+2) = 5x.\r
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\n" ); document.write( "\n" ); document.write( "But the integer  61  is not multiple of  5.  Contradiction. \r
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\n" ); document.write( "\n" ); document.write( "Hence,  the dates are partly the end of some month and the beginning of the next month. \r
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\n" ); document.write( "\n" ); document.write( "Then,  it is easy to check the the dates  27,  28,  1,  2  and 3  satisfy the condition  27 + 28 + 1 + 2 + 3 = 61. \r
\n" ); document.write( "\n" ); document.write( "Next,  it is easy to see that there is no other solution.\r
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