document.write( "Question 11876: The sum of the ages of a father and her daughter is 44 years. The father's age is 4 years more than 3 times the daughter's age. Find the ages of both. \n" ); document.write( "

Algebra.Com's Answer #6083 by elima(1433) $\"\"$ $\"About$

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The sum of the ages of a father and her daughter is 44 years. The father's age is years more than 3 times the daughter's age. Find the ages of both. \r
\n" ); document.write( "\n" ); document.write( "Let x be the daughter's age\r
\n" ); document.write( "\n" ); document.write( "The fathers age is:
\n" ); document.write( "4+3x\r
\n" ); document.write( "\n" ); document.write( "So the eqaution would be:
\n" ); document.write( "x+(4+3x)=44
\n" ); document.write( "We combine like terms:
\n" ); document.write( "x+3x+4=44
\n" ); document.write( "4x+4=44
\n" ); document.write( "We subtract 4 from both sides:
\n" ); document.write( "4x=40
\n" ); document.write( "We divide by 4 from both sides:
\n" ); document.write( "x=10 - daughters age\r
\n" ); document.write( "\n" ); document.write( "10+(4+3(10)=44
\n" ); document.write( "10+4+30=44\r
\n" ); document.write( "\n" ); document.write( "So if the both add to 44 and the daughters age is 10 then the fathers age must be 34. \n" ); document.write( "

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