document.write( "Question 987555: sarah is traveling from city A to b. the distance between these 2 cities is 185 miles and she planned to arrive at city b in 2 hrs 30 minutes. her average speed for the first 1 hr 40 minutes was 75 miles per hour. but then she realized she should slow down to dive more safely. if she still wanted to arrive at her destination on time , at what speed should she drive. \n" ); document.write( "

Algebra.Com's Answer #608299 by josgarithmetic(39623) $\"\"$ $\"About$

You can put this solution on YOUR website!

\r\n" );
document.write( "             speed        time          distance\r\n" );
document.write( "FAST          75                   \r\n" );
document.write( "SLOWER         r                    \r\n" );
document.write( "Totals                               185\r\n" );
document.write( "

\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Four variables but not nearly as bad as it appears.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"d%5Bf%5D=75%2A%285%2F3%29=125\"$
\n" ); document.write( "and
\n" ); document.write( " $\"t%5Bs%5D=2%261%2F2-1%262%2F3=5%2F2-5%2F3=%2815-10%29%2F6=5%2F6\"$
\n" ); document.write( "and then
\n" ); document.write( " $\"d%5Bs%5D=185-d%5Bf%5D=185-125=60\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "You should be able to find r. \n" ); document.write( "

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