document.write( "Question 987553: Divide 90 into two parts so that the ratio between their difference and sum is 1:9
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #608297 by ikleyn(52787)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "Answer.  40 and 50.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Solution\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let  x  be the smaller of the two parts.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Then the other part is  90-x.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Notice that the sum of these parts is precisely  90,  while the difference is  (90-x) - x = 90-2x.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Then,  according to the condition,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%2890-2x%29%2F90\" = \"1%2F9\",       ----->\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"90+-+2x\" = \"90%2F9\",\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "90 - 2x = 10,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2x = 90 - 10 = 80,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = \"80%2F2\" = 40.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Thus the smallest part is  40,  and the other part is  90-40 = 50. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );