document.write( "Question 987553: Divide 90 into two parts so that the ratio between their difference and sum is 1:9
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Algebra.Com's Answer #608297 by ikleyn(52787)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Answer. 40 and 50.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solution\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let x be the smaller of the two parts.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then the other part is 90-x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Notice that the sum of these parts is precisely 90, while the difference is (90-x) - x = 90-2x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, according to the condition,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "90 - 2x = 10,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x = 90 - 10 = 80,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thus the smallest part is 40, and the other part is 90-40 = 50. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |