document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=987506>Question 987506</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 50 centimeters longer than the width. If the perimeter of the rectangle is 220 centimeters, find the width and the length. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #608260 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=608260\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w = width<BR>\n" );
document.write( "w + 50 = length {length is 50 longer than the width}\r<BR>\n" );
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document.write( "Perimeter of a rectangle = 2(width) + 2(length)\r<BR>\n" );
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document.write( "2w + 2(w + 50) = 220 {substituted width and length into perimeter formula}<BR>\n" );
document.write( "2w + 2w + 100 = 220 {used distributive property}<BR>\n" );
document.write( "4w + 100 = 220 {combined like terms}<BR>\n" );
document.write( "4w = 120 {subtracted 100 from each side}<BR>\n" );
document.write( "w = 30 {divided each side by 4}<BR>\n" );
document.write( "w + 50 = 80 {substituted 30, in for w, into w + 50}\r<BR>\n" );
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document.write( "width = 30 cm<BR>\n" );
document.write( "length = 80 cm<BR>\n" );
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