document.write( "Question 987508: The length of a rectangle is 3 ft
\n" ); document.write( " more than twice the width, and the area of the rectangle is 77 ft2
\n" ); document.write( ". Find the dimensions of the rectangle. \r
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\n" ); document.write( "\n" ); document.write( "---once i start to work out the problem i get stuck at 2w^2+3w-77=0. I know 7*-11= -77 but do you not use the ac method to make it add up to 3?
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Algebra.Com's Answer #608259 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
L length
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\n" ); document.write( "Description: \"L=2w%2B3\"
\n" ); document.write( "\"wL=77\", the area.\r
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\n" ); document.write( "\n" ); document.write( "\"w%282w%2B3%29=77\"
\n" ); document.write( "\"2w%5E2%2B3w=77\"
\n" ); document.write( "\"2w%5E2%2B3w-77=0\"\r
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\n" ); document.write( "\n" ); document.write( "You have the right equation. Either solve by factoring or by direct use of the formula for solution of a quadratic equation. Maybe you need just to look at all the combinations for decomposing into factors!\r
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\r\n" );
document.write( "(2x  7)(x  11)\r\n" );
document.write( "or\r\n" );
document.write( "(2x  11)(x  7)\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Which will give you what you want?
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