document.write( "Question 987496: For the function f(x) = 6-(1/x+3), answer the following questions:
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document.write( "A) Domain and range
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document.write( "B) 1 to 1 or not
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document.write( "C) Continuous or not (if continuous tell where)
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document.write( "D) Increasing, decreasing, both (if both tell where), or neither
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document.write( "E) Bounded above, bounded below, bounded, or unbounded (if unbounded, tell where)
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document.write( "F) Roots \n" );
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Algebra.Com's Answer #608254 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! I am going to write this as 6- [1/(x+3)] \n" ); document.write( "That is very different from 6-(1/x) +3 \n" ); document.write( "The domain is all reals except x= -3 \n" ); document.write( "Range: look at x approaching -3 from the + side and from the - side. \n" ); document.write( "As x approaches from the + side, the fraction gets large positive 1/(-2.999+3)=1/.001=1000, and that makes the function large negative, since it is being subtracted. \n" ); document.write( "; \n" ); document.write( "And by the same approach from the negative side, it can be infinite negative as well, which subtracted, makes the range infinitely positive. \n" ); document.write( "It is DISCONTINUOUS at x=-3 \n" ); document.write( "It increases from minus infinity to 6 and decreases from positive infinity to 6 as x gets large negative. The bounds are asymptote is 6. As x gets large positive, the function goes from negative infinity to 6. \n" ); document.write( "It is 1 to 1, for while it doesn't look like it passes either horizontal or vertical line test, the function does change slightly. \n" ); document.write( "; \n" ); document.write( "Solving for roots, -1/(x+3)=-6 \n" ); document.write( "6x+18=1 \n" ); document.write( "6x=-17 \n" ); document.write( "x= -(17/6)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |