document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=987460>Question 987460</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.<BR>\n" );
document.write( " the length of the sides of a triangle are x+2,2x+3 and 5x. If perimeter is 21 find the lengths of the sides?<BR>\n" );
document.write( "              the length of the shorts side is?<BR>\n" );
document.write( "              the length of the longest side is?<BR>\n" );
document.write( "               the length of the intermediate is? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #608218 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=608218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + 2 + 2x + 3 + 5x = 21  {perimeter of triangle is 21}<BR>\n" );
document.write( "8x + 5 = 21 {combined like terms}<BR>\n" );
document.write( "8x = 16 {subtracted 5 from each side}<BR>\n" );
document.write( "x = 2 {divided each side by 8}\r<BR>\n" );
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document.write( "x + 2 = 4 {substituted 2, in for x, into x + 2}<BR>\n" );
document.write( "2x + 3 = 7 {substituted 2, in for x, into 2x + 3}<BR>\n" );
document.write( "5x = 10 {substituted 2, in for x, into 5x}\r<BR>\n" );
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document.write( "short side is 4<BR>\n" );
document.write( "longest side is 10<BR>\n" );
document.write( "intermediate side is 7<BR>\n" );
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