document.write( "Question 987437: there were three times as many children a there were adults in attendance at a party. altogether there were 56 guests. how many of the quests were children? \n" ); document.write( "
Algebra.Com's Answer #608206 by macston(5194)![]() ![]() You can put this solution on YOUR website! A=number of adults; C=number of children=3A \n" ); document.write( "A+C=56 \n" ); document.write( "A+3A=56 \n" ); document.write( "4A=56 \n" ); document.write( "A=14 \n" ); document.write( "There were 14 adult guests. \n" ); document.write( "C=3A=3(14)=42 \n" ); document.write( "ANSWER: There were 42 children at the party. \n" ); document.write( " \n" ); document.write( " |