document.write( "Question 987279: PLEASE HELP ME :(
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document.write( "You have purchased a 42-inch television with an aspect ratio of 16:9. You want to watch a movie which has an aspect ratio of 1.85:1. Find the following measurements.\r
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document.write( " Height of the television screen\r
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document.write( " Width of the television screen\r
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document.write( " Height of the black bars at the top and bottom of the screen.\r
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document.write( " Percent of the area of the television screen that is covered by the image. \n" );
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Algebra.Com's Answer #608192 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! You have purchased a 42-inch television with an aspect ratio of 16:9. You want to watch a movie which has an aspect ratio of 1.85:1. Find the following measurements.\r \n" ); document.write( "\n" ); document.write( " Height of the television screen \n" ); document.write( "----------------- \n" ); document.write( "For 16:9 TV: \n" ); document.write( "d^2 = 9^2 + 16^2 = 337 \n" ); document.write( "For 42\" diagonal: \n" ); document.write( "d^2 = (q*9)^2 + (q*16)^2 = 42^2 = 1764 \n" ); document.write( "337q^2 = 1764 \n" ); document.write( " \n" ); document.write( "W = 16q = 36.6 \n" ); document.write( "H = 9q = 20.6 \n" ); document.write( "======================= \n" ); document.write( "Width of the television screen \n" ); document.write( "See above. \n" ); document.write( "====================== \n" ); document.write( "Height of the black bars at the top and bottom of the screen. \n" ); document.write( "****************More tomorrow.\r \n" ); document.write( "\n" ); document.write( " Percent of the area of the television screen that is covered by the image. \n" ); document.write( " |