document.write( "Question 987420: Ok it goes like this. The perimeter of a triangle is 55. The side Ab is 70% of the side Dc. The side BC is 3 cms more than the side Ab. Calculate the value of the sides. \n" ); document.write( "
Algebra.Com's Answer #608185 by macston(5194)\"\" \"About 
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\n" ); document.write( "I am adjusting DC to be AC. If this is not correct, re-post your problem.
\n" ); document.write( ".
\n" ); document.write( "AC=AC
\n" ); document.write( "AB=0.7AC
\n" ); document.write( "BC=0.7AC+3cm
\n" ); document.write( ".
\n" ); document.write( "Perimeter=AB+BC+AC
\n" ); document.write( "Perimeter=0.7AC+(0.7AC+3cm)+AC
\n" ); document.write( "Perimeter=2.4AC+3cm
\n" ); document.write( "55cm=2.4AC+3cm
\n" ); document.write( "52cm=2.4AC
\n" ); document.write( "21.67cm=AC
\n" ); document.write( "ANSWER 1:AC=21.67 cm
\n" ); document.write( ".
\n" ); document.write( "AB=0.7AC=(0.7)(21.67)=15.17cm
\n" ); document.write( "ANSWER 2: AB=15.17cm
\n" ); document.write( ".
\n" ); document.write( "BC=0.7AC+3cm=15.17cm+3cm=18.17cm
\n" ); document.write( "ANSWER 3: BC=18.17cm
\n" ); document.write( ".
\n" ); document.write( "CHECK:
\n" ); document.write( "Perimeter=55cm
\n" ); document.write( "AB+BC+AC=55cm
\n" ); document.write( "15.17cm+18.17cm+21.67cm=55cm
\n" ); document.write( "55.01cm=55cm\r
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