document.write( "Question 987424: How many gallons of a 9% salt solution must be mixed with 35 gallons of a 11% solution to obtain a 10% solution? \n" ); document.write( "
Algebra.Com's Answer #608182 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "x=gallons of 9% solution needed. \n" ); document.write( ". \n" ); document.write( "0.09x+0.11(35gal)=0.10(35gal+x) \n" ); document.write( "0.09x+3.85gal=3.5gal+0.10x \n" ); document.write( "0.35gal=0.01x \n" ); document.write( "35gal=x \n" ); document.write( ". \n" ); document.write( "ANSWER: 35 gallons of 9% solution should be used. \n" ); document.write( ". \n" ); document.write( "CHECK: \n" ); document.write( "0.09x+0.11(35gal)=0.10(35gal+x) \n" ); document.write( "0.09(35gal)+0.11(35gal)=0.10(35gal+35gal) \n" ); document.write( "3.15gal+3.65gal=0.10(70gal) \n" ); document.write( "7.0gal=7.0gal\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |