document.write( "Question 987424: How many gallons of a 9% salt solution must be mixed with 35 gallons of a 11% solution to obtain a 10% solution? \n" ); document.write( "
Algebra.Com's Answer #608182 by macston(5194)\"\" \"About 
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\n" ); document.write( "x=gallons of 9% solution needed.
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\n" ); document.write( "0.09x+0.11(35gal)=0.10(35gal+x)
\n" ); document.write( "0.09x+3.85gal=3.5gal+0.10x
\n" ); document.write( "0.35gal=0.01x
\n" ); document.write( "35gal=x
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\n" ); document.write( "ANSWER: 35 gallons of 9% solution should be used.
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\n" ); document.write( "CHECK:
\n" ); document.write( "0.09x+0.11(35gal)=0.10(35gal+x)
\n" ); document.write( "0.09(35gal)+0.11(35gal)=0.10(35gal+35gal)
\n" ); document.write( "3.15gal+3.65gal=0.10(70gal)
\n" ); document.write( "7.0gal=7.0gal\r
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