document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=987414>Question 987414</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the values of a and b so that the curve y= a * b^x passes through the points (1,6) and (-1, 3/2), given that b>0\r<BR>\n" );
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document.write( "I can't seem to find relevant information on this type of problem, so i'm not even really sure how to start.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #608167 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39625)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=608167\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take logarithms of both sides of the equation and this gives a linear equation.  Also take the logarithms of the y-coordinates of your given points and then use these as points for your linearized form of the equation.  You can then use your earlier learned concepts and skills about linear equations and lines.\r<BR>\n" );
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document.write( "After done correctly, if using base-ten logarithms, the equation should be equivalent to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%2810%2Cy%29=%28log%2810%2Cb%29%29x%2Blog%2810%2Ca%29 ALIGN=MIDDLE  ALT=\"log%2810%2Cy%29=%28log%2810%2Cb%29%29x%2Blog%2810%2Ca%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, and your converted given points are  (1, log(6)) and  (-1, log(1.5)).\r<BR>\n" );
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document.write( "Use these two points and the formula for slope based on two known points.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%2810%2Cb%29=%28log%2810%2C6%29-log%2810%2C%283%2F2%29%29%29%2F%281-%28-1%29%29 ALIGN=MIDDLE  ALT=\"log%2810%2Cb%29=%28log%2810%2C6%29-log%2810%2C%283%2F2%29%29%29%2F%281-%28-1%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Keep working with that to simplify as much as possible, and you should find  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=log%2810%2Cb%29=log%2810%2C2%29 ALIGN=MIDDLE  ALT=\"log%2810%2Cb%29=log%2810%2C2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "meaning obviously,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28b=2%29 ALIGN=MIDDLE  ALT=\"highlight%28b=2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "You still want to determine the value for \"a\".  You can do this... </SPAN>\n" );
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