document.write( "Question 987387: A boardwalk is parallel to and 210 ft inland from a straight shoreline. A sandy beach lies between the boardwalk and the shoreline. A man is standing on the boardwalk, exactly 750 ft across the sand from his beach umbrella, which is right at the shoreline. The man walks 4 ft/s on the boardwalk and 2 s on the sand. How far should he walk on the boardwalk before veering off onto the sand if he wishes to reach his umbrella in exactly 4 min 45 s? \n" ); document.write( "

Algebra.Com's Answer #608164 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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Actually, it comes out to him walking 720' on the boardwalk to a point opposite from the umbrella. Takes a 90 degree left turn walks 210' ft across the sand.
\n" ); document.write( ":
\n" ); document.write( "Change 4 min 45 sec to 285 sec
\n" ); document.write( "time = $\"720%2F4\"$ + $\"210%2F2\"$
\n" ); document.write( "time = 180 + 105
\n" ); document.write( "time = 285 sec which is 4 min 45 sec \n" ); document.write( "

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