document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=987380>Question 987380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The longest side of an acute isosceles triangle is 12 centimeters. Rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #608145 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=608145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If the triangle were a right triangle, the sides would be 12/sqrt (2)= 6 sqrt(2), 8.484 cm.  If the angle were obtuse, even a little, the two sides would be shorter, so the sides have to be longer, and we will round up to 8.5 cm.  <BR>\n" );
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