document.write( "Question 987353: I don't understand how to do the problem: \"x%2F4\" = \"2%2B%28x-3%29%2F3\". \n" ); document.write( "
Algebra.Com's Answer #608086 by ikleyn(52798)\"\" \"About 
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\n" ); document.write( "You have an equation\r
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\n" ); document.write( "\n" ); document.write( "\"x%2F4\" = \"2%2B%28x-3%29%2F3\".\r
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\n" ); document.write( "\n" ); document.write( "The common denominator of the ratios in the left and the right sides of the equation is  12. \r
\n" ); document.write( "\n" ); document.write( "Multiply both sides of the equation by the common denominator  12.  You will get\r
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\n" ); document.write( "\n" ); document.write( "3x = 24 + 4*(x-3). \r
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\n" ); document.write( "\n" ); document.write( "Now,  open parentheses in the right side:\r
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\n" ); document.write( "\n" ); document.write( "3x = 24 + 4x - 12. \r
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\n" ); document.write( "\n" ); document.write( "Collect common terms:\r
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\n" ); document.write( "\n" ); document.write( "3x - 4x = 24 - 12,     or\r
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\n" ); document.write( "\n" ); document.write( "-x = 12.\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by  -1.  You will get \r
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\n" ); document.write( "\n" ); document.write( "x = -12.\r
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\n" ); document.write( "\n" ); document.write( "Congratulations!  You just solved the equation. \r
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\n" ); document.write( "\n" ); document.write( "Now check your solution.  Substitute the found value of  x = -12  into the left side of the original equation.  You will get \r
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\n" ); document.write( "\n" ); document.write( "\"-12%2F4\" = -3. \r
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\n" ); document.write( "\n" ); document.write( "Next,  substitute  x = -12  into the right side of the original equation.  You will get \r
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\n" ); document.write( "\n" ); document.write( "\"2%2B%28x-3%29%2F3\" = \"2+%2B%28-12-3%29%2F3\" = \"2+%2B+%28-15%29%2F3\" = \"2+%2B+%28-5%29\" = \"2-5\" = \"-3\".\r
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\n" ); document.write( "\n" ); document.write( "Hence,  your solution is correct. \r
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\n" ); document.write( "\n" ); document.write( "Good job!\r
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