document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=987308>Question 987308</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a triangle PQR is such that line PQ is equal to line PR.<BR>\n" );
document.write( "Given that angle PQR is 40 degrees find the length of PR if the area of the triangle is 240 centimeters squared. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #608062 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=608062\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "If the size of PQ and PR = x<BR>\n" );
document.write( "Area = 1/2 q*r*sin(40)<BR>\n" );
document.write( "240 = 1/2 x * x * sin(40)<BR>\n" );
document.write( "240 = 1/2 x^2 sin(40)<BR>\n" );
document.write( "Multiply both sides by 2<BR>\n" );
document.write( "480 = x^2sin(40)<BR>\n" );
document.write( "Divide both sides by sin(40)<BR>\n" );
document.write( "480/sin(40) = x^2<BR>\n" );
document.write( "x = &#8730;480/sin(40)<BR>\n" );
document.write( "x = 27.3cm<BR>\n" );
document.write( "PR = PQ = 27.3cm<BR>\n" );
document.write( "Hope this helps :-)<BR>\n" );
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