document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=11889>Question 11889</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pleased help me sir....<BR>\n" );
document.write( " How many grams of an alloy containing 35% nickel must be melted with an alloy containing 65% nickel in order to obtain 20 grams of an alloy containing 41% nickel? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6080 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> After changing the percentages to decimals, you can set up your equation as follows: x = number of grams of the 35% Ni alloy. (35% = 0.35, 65% = 0.65, 41% = 0.41)\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%280.35%29+%2B+%2820+-+x%29%280.65%29+=+%2820%29%280.41%29 ALIGN=MIDDLE  ALT=\"x%280.35%29+%2B+%2820+-+x%29%280.65%29+=+%2820%29%280.41%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >  Simplify and solve for x.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0.35x+%2B+13+-+0.65x+=+8.2 ALIGN=MIDDLE  ALT=\"0.35x+%2B+13+-+0.65x+=+8.2\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-0.3x+%2B+13+=+8.2 ALIGN=MIDDLE  ALT=\"-0.3x+%2B+13+=+8.2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Subtract 13 from both sides.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-0.3x+=+-4.8 ALIGN=MIDDLE  ALT=\"-0.3x+=+-4.8\"   DISABLED_style= \"max-width:90%; height:auto;\" > Divide both sides by -0.3\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+16 ALIGN=MIDDLE  ALT=\"x+=+16\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "16 grams of 35% Ni alloy are required.\r<BR>\n" );
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