document.write( "Question 84317: .5c + 5a + 3s = 100
\n" ); document.write( "c + a + s = 100\r
\n" ); document.write( "\n" ); document.write( "There is a fair where childs tickets cost $0.50 and adults tickets cost $5.00 each and senior citizens tickets cost $3.00. The total amount of tickets sold adds up to be $100.00. The total number of tickets sold is 100 also. How many children, adults, and seniors went to the fair?
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Algebra.Com's Answer #60799 by ankor@dixie-net.com(22740)\"\" \"About 
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.5c + 5a + 3s = 100
\n" ); document.write( "c + a + s = 100
\n" ); document.write( "There is a fair where childs tickets cost $0.50 and adults tickets cost $5.00 each and senior citizens tickets cost $3.00. The total amount of tickets sold adds up to be $100.00. The total number of tickets sold is 100 also. How many children, adults, and seniors went to the fair?
\n" ); document.write( ":
\n" ); document.write( "multiply the 1st equation by 2 and subtract the 2nd equation from it:
\n" ); document.write( "1c + 10a + 6s = 200
\n" ); document.write( "1c + 1a + 1s = 100
\n" ); document.write( "--------------------subtraction eliminates c
\n" ); document.write( "0c + 9a + 5s = 100
\n" ); document.write( "5s = 100 - 9a
\n" ); document.write( "s = 100/5 - 9a/5
\n" ); document.write( "s = 20 - 9a/5
\n" ); document.write( ":
\n" ); document.write( "We know that both s and a have to be integers, this narrows the value of \"a\" down to a multiply of 5. Start with a = 5 and see what we have:
\n" ); document.write( ":
\n" ); document.write( "s = 20 - (9*5)/5
\n" ); document.write( "s = 20 - 45/5
\n" ); document.write( "s = 20 - 9
\n" ); document.write( "s = 11 seniors and
\n" ); document.write( "a = 5 adults
\n" ); document.write( ":
\n" ); document.write( "Find c:
\n" ); document.write( "c + 5 + 11 = 100
\n" ); document.write( "c = 100 - 16
\n" ); document.write( "c = 84 children:
\n" ); document.write( ":
\n" ); document.write( "Check all 3 solutions in the 2nd equation:
\n" ); document.write( ".5(84) + 5(5) + 3(11) =
\n" ); document.write( " 42 + 25 + 33 = 100
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