document.write( "Question 987202: PLEASE PLEASE HELP I can't seem to figure out how to do these four problems.\r
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document.write( "My kids’ bathtub is being drained. Since it is an ordinary tub, it can be modeled by the function
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document.write( "V(t) = -15t + 45 where V(t) is the volume of the tub in gallons and t is the time that has passed in minutes.\r
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document.write( "1.Based on the function V(t) = -15t + 45, when will the tub be half full?\r
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document.write( "2.What is the practical domain in this problem? Use appropriate notation in your answer.\r
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document.write( "3.What is the practical range? Use the appropriate notation in your answer.\r
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document.write( "4.My tub is a garden tub. When I drain it I can model the volume of water in it by
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document.write( "v(T) = -20T + 50 where v(T) is the volume of the tub in gallons and T is the time that has passed
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document.write( "in minutes. Given all this, which tub drains faster, my kids’ tub, or mine? Explain your reasoning. \n" );
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Algebra.Com's Answer #607979 by macston(5194)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "1. When t=0, the tub has not yet started to drain: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The total volume of the tub is 45 gallons. \n" ); document.write( "The tub will be half full when V(t)=(1/2)(45gal)=22.5gal: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "ANSWER: The tub will be half empty in 1.5 minutes. \n" ); document.write( ". \n" ); document.write( "2. Domain: [0,3] \n" ); document.write( "Since t is time, it is not less than zero. So 0<=t. \n" ); document.write( "If t>3, the volume is negative so t<=3. \n" ); document.write( ". \n" ); document.write( "3. Range: [0,45] \n" ); document.write( "V(t) is volume, cannot be less than zero: 0<+V(t) \n" ); document.write( "At t=0, the tub is full at 45 gallons, so: V(t)<=45 \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "4. Kid's tub, t when V(t)=0 is time to drain fully: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "It takes 3 minutes to drain this tub completely. \n" ); document.write( ". \n" ); document.write( "For the garden tub when V(t)=0: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "It takes 2.5 minutes to completely drain the garden tub. \n" ); document.write( ". \n" ); document.write( "ANSWER: The garden tub drains faster. \n" ); document.write( "REASONING: The kid's tub drains 45 gal/3 min=15 gal/min. \n" ); document.write( "The garden tub drains 50 gal/2.5 min=20gal/min. \n" ); document.write( "The garden tub drains more water in less time. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |