document.write( "Question 987172: A woman is 3 times as old as her son.8 years ago the product of their age was 112.find their present age \n" ); document.write( "
Algebra.Com's Answer #607950 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "A woman is 3 times as old as her son. \n" ); document.write( "W = 3S \n" ); document.write( "8 years ago the product of their age was 112. \n" ); document.write( "(W - 8)(S - 8) = 112 \n" ); document.write( "Replace W with 3s from top equation \n" ); document.write( "(3S - 8)(S - 8) = 112 \n" ); document.write( "Multiply out \n" ); document.write( "3S^2 - 32S + 64 = 0 \n" ); document.write( "Factorise \n" ); document.write( "(3S + 4)(S - 12) = 0 \n" ); document.write( "3S + 4 = 0 \n" ); document.write( "3S = -4 \n" ); document.write( "S = -4/3 (No answer as -ve) \n" ); document.write( "S - 12 = 0 \n" ); document.write( "S = 12 \n" ); document.write( "Son is 12 years old \n" ); document.write( "Woman is 36 years old \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |