document.write( "Question 987172: A woman is 3 times as old as her son.8 years ago the product of their age was 112.find their present age \n" ); document.write( "
Algebra.Com's Answer #607950 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "A woman is 3 times as old as her son.
\n" ); document.write( "W = 3S
\n" ); document.write( "8 years ago the product of their age was 112.
\n" ); document.write( "(W - 8)(S - 8) = 112
\n" ); document.write( "Replace W with 3s from top equation
\n" ); document.write( "(3S - 8)(S - 8) = 112
\n" ); document.write( "Multiply out
\n" ); document.write( "3S^2 - 32S + 64 = 0
\n" ); document.write( "Factorise
\n" ); document.write( "(3S + 4)(S - 12) = 0
\n" ); document.write( "3S + 4 = 0
\n" ); document.write( "3S = -4
\n" ); document.write( "S = -4/3 (No answer as -ve)
\n" ); document.write( "S - 12 = 0
\n" ); document.write( "S = 12
\n" ); document.write( "Son is 12 years old
\n" ); document.write( "Woman is 36 years old
\n" ); document.write( "Hope this helps :-)
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