document.write( "Question 987129: The product of two consecutive odd integers is 58 less than the square of the next consecutive integer. Find the three integers. \n" ); document.write( "
Algebra.Com's Answer #607945 by macston(5194)\"\" \"About 
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\n" ); document.write( "x and x+2 are consecutive odd integers. x+4=next consecutive odd integer.
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\n" ); document.write( "\"%28x%29%28x%2B2%29=%28x%2B4%29%5E2-58\"
\n" ); document.write( "\"x%5E2%2B2x=x%5E2%2B8x%2B16-58%7D%7D%0D%0A%7B%7B%7B0=6x-42\"
\n" ); document.write( "\"0=x-7\"
\n" ); document.write( "\"7=x\"
\n" ); document.write( "ANSWER 1: the first integer is 7.
\n" ); document.write( "second integer=x+2=7+2=9
\n" ); document.write( "ANSWER 2: The second integer is 9.
\n" ); document.write( "third integer=x+4=7+4=11
\n" ); document.write( "ANSWER 3: The third integer is 11.
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\n" ); document.write( "CHECK:
\n" ); document.write( "\"%287%29%289%29=%2811%29%5E2-58\"
\n" ); document.write( "\"63=121-58\"
\n" ); document.write( "\"63=63\"\r
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