document.write( "Question 987166: write a quadratic equation whose solutions are 1+2i and 1 - 2i
\n" ); document.write( "the equation is x^2-_x+_=0\r
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Algebra.Com's Answer #607934 by ikleyn(52780) $\"\"$ $\"About$

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\n" ); document.write( "(x - (1+2i))*(x - (1-2i)).\r
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\n" ); document.write( "\n" ); document.write( "The constant term is the product (1+2i)*(1-2i) = $\"1%5E2\"$ - $\"%282i%29%5E2\"$ = 1 - 4*(-1) = 1 + 4 = 5.\r
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\n" ); document.write( "\n" ); document.write( "The coefficient at x is -[(1+2i) + (1-2i)] = -2.\r
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\n" ); document.write( "\n" ); document.write( "Hence, the quadratic equation is \r
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\n" ); document.write( "\n" ); document.write( " $\"x%5E2\"$ - $\"2x\"$ + $\"5\"$ = $\"0\"$ .\r
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