document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=987084>Question 987084</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of a supplement of a angle is 24 degrees more than three times the measure of the original angle. find the measures of the angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607858 by </B><A HREF=/tutors/aboutme.mpl?userid=macston><B>macston(5194)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=macston><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=macston><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "x=original angle; s=supplement=3x+24<BR>\n" );
document.write( ".<BR>\n" );
document.write( "x+s=180<BR>\n" );
document.write( "x+(3x+24)=180<BR>\n" );
document.write( "4x=156<BR>\n" );
document.write( "x=39<BR>\n" );
document.write( "ANSWER 1: The original angle is 39 degrees.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "s=3x+24<BR>\n" );
document.write( "s=3(39)+24<BR>\n" );
document.write( "s=117+24=141<BR>\n" );
document.write( "ANSWER 2: The supplement is 141 degrees. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );