document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986929>Question 986929</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If the sum of the measures of two angles is 90 degrees, the angles are complementary.  Thus, if the measure of an angle is A degrees, the measure of the compliment is (90 - A)degrees.  Find an angle whose measure is 3 greater than twice the measure of its compliment. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607715 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52790)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Let &nbsp;<B>x</B>&nbsp; be the measure of the unknown angle (in degrees). \r<BR>\n" );
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document.write( "Then the measure of its complement is &nbsp;(90° - x), &nbsp;and we have an equation \r<BR>\n" );
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document.write( "x - 3 = 2(90-x).\r<BR>\n" );
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document.write( "Solve it:\r<BR>\n" );
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document.write( "x - 3 = 180 - 2x,\r<BR>\n" );
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document.write( "x + 2x = 180 + 3\r<BR>\n" );
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document.write( "3x = 183\r<BR>\n" );
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document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=183%2F3 ALIGN=MIDDLE  ALT=\"183%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 61. \r<BR>\n" );
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document.write( "<B>Answer</B>. &nbsp;61°.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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