document.write( "Question 986899: The product of two numbers is -192 and their sum is 4. What are the two numbers? \n" ); document.write( "
Algebra.Com's Answer #607702 by Alan3354(69443) You can put this solution on YOUR website! The product of two numbers is -192 and their sum is 4. What are the two numbers? \n" ); document.write( "====================== \n" ); document.write( "Find a pair of factors of 192 that differ by 4. One is negative, one is positive. \n" ); document.write( "---- \n" ); document.write( "1*192 NG \n" ); document.write( "2*96 NG \n" ); document.write( "etc. \n" ); document.write( "================== \n" ); document.write( "Or, do all this: \n" ); document.write( "===================================================== \n" ); document.write( "The product of two numbers is -192 \n" ); document.write( " xy = -192 \n" ); document.write( " Their sum = 4 \n" ); document.write( " x + y = 4 \n" ); document.write( " y = 4 - x \n" ); document.write( " Substitute 4 - x into \n" ); document.write( " equation xy = -192 \n" ); document.write( " x(4 - x) = -192 \n" ); document.write( " Multiply out: \n" ); document.write( " = 4x - x^2 = -192 \n" ); document.write( " Sort out \n" ); document.write( " 192 + 4x - x^2 = 0 \n" ); document.write( " Factorise: \n" ); document.write( "************************ \n" ); document.write( "*************** Then at this point, find a pair of factors of 192 that differ by 4. \n" ); document.write( "************************ \n" ); document.write( " (12 + x)(16 + x-) = 0 \n" ); document.write( " 12 + x = 0 \n" ); document.write( " |