document.write( "Question 986866: Im not sure how to factor and simplify this (x+3)^(1/2)-(x+3)^(3/2)\r
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Algebra.Com's Answer #607638 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let \"z+=+%28x%2B3%29%5E%281%2F2%29%5E%22%22\"\r
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\n" ); document.write( "\n" ); document.write( "If we cube both sides of the equation above, we get \"z%5E3+=+%28%28x%2B3%29%5E%281%2F2%29%5E%22%22%29%5E3+=+%28x%2B3%29%5E%283%2F2%29\"\r
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\n" ); document.write( "\n" ); document.write( "This means the original expression \"%28x%2B3%29%5E%281%2F2%29%5E%22%22-%28x%2B3%29%5E%283%2F2%29\" is equivalent to \"z-z%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "we can factor out a 'z' to get \"z-z%5E3=z%281-z%5E2%29\"\r
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\n" ); document.write( "\n" ); document.write( "Then use the difference of squares law \"z%281-z%5E2%29=z%281-z%29%281%2Bz%29\"\r
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\n" ); document.write( "\n" ); document.write( "So, \"z-z%5E3=z%281-z%29%281%2Bz%29\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace each 'z' with \"%28x%2B3%29%5E%281%2F2%29%5E%22%22\"\r
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\n" ); document.write( "\n" ); document.write( "\"z-z%5E3=z%281-z%29%281%2Bz%29\"\r
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\n" ); document.write( "\n" ); document.write( "Yes it's very ugly, but it's a factored form of the original expression\r
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\n" ); document.write( "\n" ); document.write( "The fully factored form is
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