document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986856>Question 986856</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An object is propelled vertically upward with an initial velocity of 20 meters per second. The distance s (in meters) of object from ground after t seconds is s=-4.9t( squared) +20t. When will object be 15 meters above ground? \r<BR>\n" );
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document.write( "Is this set up like 15=-4.9tsquared+20t?? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607633 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607633\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An object is propelled vertically upward with an initial velocity of 20 meters per second. The distance s (in meters) of object from ground after t seconds is s=-4.9t( squared) +20t. When will object be 15 meters above ground? \r<BR>\n" );
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document.write( "Is this set up like 15=-4.9tsquared+20t??<BR>\n" );
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document.write( "Yes, exactly like that.<BR>\n" );
document.write( "Solve for t.<BR>\n" );
document.write( "There might be 2 values for t, 1 going up, another descending. </SPAN>\n" );
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