document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986825>Question 986825</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles form a linear pair. The measure of one angle is 1/3 the measure of the other angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607610 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607610\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles form a linear pair. The measure of one angle is 1/3 the measure of the other angle.<BR>\n" );
document.write( "------<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "x + y = 180 degrees<BR>\n" );
document.write( "x = (1/3)y<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "Substitute for \"x\" and solve for \"y\"::<BR>\n" );
document.write( "(1/3)y + y = 180<BR>\n" );
document.write( "(4/3)y = 180<BR>\n" );
document.write( "y = (3/4)180<BR>\n" );
document.write( "y = 135 degrees<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Solve for \"x\":<BR>\n" );
document.write( "x + y = 180<BR>\n" );
document.write( "x + 135 = 180<BR>\n" );
document.write( "x = 45 degrees<BR>\n" );
document.write( "---------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "----------------- </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );