document.write( "Question 986809: The dimensions of a rectangle are such that it's length is 7in more than its width. If the length were doubled and if the width were decreased by 3 in, the area would be increased by 168 in^2. What are the length and width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #607601 by josgarithmetic(39617)\"\" \"About 
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w and L for original dimensions;
\n" ); document.write( "\"L=7%2Bw\", given;
\n" ); document.write( "\"A=wL=w%28w%2B7%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Changed dimensions;
\n" ); document.write( "\"2L=2%28w%2BL%29\" for length;
\n" ); document.write( "-
\n" ); document.write( "\"w-3\" for width;
\n" ); document.write( "\"2L%28w-3%29-wL=168\", should make sense.
\n" ); document.write( "Work with this and find w and L.
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