document.write( "Question 986738: Could you help mi figure out the value of a in the following formula\r
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document.write( "SecA + CscA = 3
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document.write( "solve for angle a, and please include work \n" );
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Algebra.Com's Answer #607570 by Alan3354(69443) You can put this solution on YOUR website! SecA + CscA = 3 \n" ); document.write( " solve for angle a \n" ); document.write( " ============== \n" ); document.write( " (1/cos) + (1/sin) = 3 \n" ); document.write( " (sin + cos)/sin*cos = 3 \n" ); document.write( " sin + cos = 3sin*cos \n" ); document.write( " Square both sides \n" ); document.write( " sin^2 + 2sin*cos + cos^2 = 9sin^2cos^2 \n" ); document.write( " cos^2 = 1 - sin^2 \n" ); document.write( " sin^2 + 2sin*cos + 1 - sin^2 = 9sin^2(1 - sin^2) = 9sin^2 - 9sin^4 \n" ); document.write( " 2sin*cos + 1 = 9sin^2 - 9sin^4 \n" ); document.write( " 2sin*cos + sin^2 + cos^2 = 9sin^2 - 9sin^4 \n" ); document.write( "=========================== \n" ); document.write( "I see no option other than graphical or iterative methods. \n" ); document.write( "============================= \n" ); document.write( "A =~0.59045279001103 \n" ); document.write( "A =~0.98034353678387 \n" ); document.write( "A =~2.890976773032889 \n" ); document.write( "A =~4.963004860941594 \n" ); document.write( "------------------------- \n" ); document.write( "It's periodic, period of 2pi\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |