document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986779>Question 986779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One leg Of a right triangle Is 5 inches lInter than the other. If the hypotenuse is 25 inches long, Find the lengths of the legs.(only an algerbraic solution will be accepted) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607568 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607568\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "One leg is 5 ins. shorter than<BR>\n" );
document.write( "other leg.<BR>\n" );
document.write( "Other leg = 'x'<BR>\n" );
document.write( "One leg = x - 5<BR>\n" );
document.write( "Hypotenuse = 25 ins<BR>\n" );
document.write( "x^2 + (x - 5)^2 = 25^2<BR>\n" );
document.write( "x^2 + x^2 - 10 + 25 = 625<BR>\n" );
document.write( "2x^2 - 10x - 600 = 0<BR>\n" );
document.write( "Divide thro' by 2<BR>\n" );
document.write( "x^2 - 5x - 300 = 0<BR>\n" );
document.write( "Factorise<BR>\n" );
document.write( "(x - 20)(x + 15) = 0<BR>\n" );
document.write( "x + 15 = 0<BR>\n" );
document.write( "x = -15 (no answer as -ve)<BR>\n" );
document.write( "x - 20 = 0<BR>\n" );
document.write( "x = 20<BR>\n" );
document.write( "Other leg = 20 inches<BR>\n" );
document.write( "One leg = 15 inches<BR>\n" );
document.write( "Hypotenuse = 25 inches.<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );