document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=986739>Question 986739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Let x-2,2&#8730;	3, x-3  be the first 3 terms of a geometric sequence. Find the value of x (the quadratic equation can be solved by factoring). </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #607521 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52780)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=607521\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .<BR>\n" );
document.write( "Since &nbsp;<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-2 ALIGN=MIDDLE  ALT=\"x-2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, &nbsp;<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2sqrt%283%29 ALIGN=MIDDLE  ALT=\"2sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >&nbsp;and &nbsp;<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x-3%29 ALIGN=MIDDLE  ALT=\"x-3%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >&nbsp; are the first &nbsp;3&nbsp; terms of a geometric sequence, &nbsp;you have a proportion\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2sqrt%283%29%2F%28x-2%29 ALIGN=MIDDLE  ALT=\"2sqrt%283%29%2F%28x-2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28x-3%29%2F%282sqrt%283%29%29 ALIGN=MIDDLE  ALT=\"%28x-3%29%2F%282sqrt%283%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "(saying that the ratio of the second term to the first one is equal to the ratio of the third term to the second one). \r<BR>\n" );
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document.write( "From the proportion,\r<BR>\n" );
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document.write( "(x-2)*(x-3) = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%282sqrt%283%29%29%5E2 ALIGN=MIDDLE  ALT=\"%282sqrt%283%29%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 4*3 = 12.\r<BR>\n" );
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document.write( "Hence,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+-+2x+-+3x+%2B+6 ALIGN=MIDDLE  ALT=\"x%5E2+-+2x+-+3x+%2B+6\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12 ALIGN=MIDDLE  ALT=\"12\"   DISABLED_style= \"max-width:90%; height:auto;\" >,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%5E2+-+5x+-+6 ALIGN=MIDDLE  ALT=\"x%5E2+-+5x+-+6\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0 ALIGN=MIDDLE  ALT=\"0\"   DISABLED_style= \"max-width:90%; height:auto;\" >,\r<BR>\n" );
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document.write( "(x+1)*(x-6) = 0.\r<BR>\n" );
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document.write( "The roots are &nbsp;-1 &nbsp;and &nbsp;6. \r<BR>\n" );
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document.write( "<B>Answer</B>. &nbsp;x = -1 &nbsp;or &nbsp;x = 6.\r<BR>\n" );
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